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  #26  
Old 09/30/2007, 01:38 AM
musty baby musty baby is offline
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Actually, I think you're all off

The sun is on average 150 million km away from the earth. The area of the imaginary sphere at the distance of the earth is 4*pi*150 000 000^2, or 2.83*10^17 km^2.

The earth is about 12735 km wide. The cross section of earth perpendicular to the sun is about pi(12735/2)^2 or 127 376 050 km^2.

By that, the earth receives (127 376 050/2.83*10^17)*100 or .000 000 045 percent of the sun's radiation.

Simple proportion - if we receive 174 petawatts and we are .000 000 045% of the area bombarded by the sun's radiation, then 100*174/.000 000 045 should equal around the number of petawatts total. 386 666 666 667 petawatts.

386 666 666 667 000 000 000 000 000 watts.

Hooray. I am officially lame
  #27  
Old 09/30/2007, 01:41 AM
musty baby musty baby is offline
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Oops. I guess I missed jetcat's first post!
  #28  
Old 09/30/2007, 01:56 AM
T Man T Man is offline
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Quote:
Originally posted by ryansholl
Actually, I think you're all off
  #29  
Old 09/30/2007, 02:01 AM
steve70 steve70 is offline
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over my head, talk english, lol
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  #30  
Old 09/30/2007, 03:22 AM
musty baby musty baby is offline
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Whoa buddy. I meant "oops didn't see T Man's post".

Your book = 3.85x10^26 watts

My crummy math = 3.87x10^26 watts

  #31  
Old 09/30/2007, 07:41 AM
Adam G Adam G is offline
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Can you guys figure up some numbers to show how many watts it would take to match the power of the sun in an aqaurium?

Let's assume that we take the amount of sunlight in clear ocean water at a depth of 30ft on the equater.

How many watts to match this amount of light in an aquarium at a depth of 1 ft?
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  #32  
Old 09/30/2007, 07:49 AM
Pmolan Pmolan is offline
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Quote:
Originally posted by T Man

Did you just scan this in??

  #33  
Old 09/30/2007, 07:54 AM
sabbath sabbath is offline
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Quote:
Originally posted by Travis L. Stevens
Uhh.... no

PAR Readings
Oklahoma sun at 5pm at street level: ~1800
4x 54w T5HO with individual Reflectors at water surface: ~300-500 depending on bulbs/ballast
1x 250w SE Metal Halide: ~200-400 depending on bulb/ballast
Good question. I wonder what the par reading is in the oceans right on top of the coral reefs. Is our lights getting close to the par that they are used to.
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  #34  
Old 09/30/2007, 09:03 AM
JetCat USA JetCat USA is offline
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Quote:
Originally posted by Adam G
Let's assume that we take the amount of sunlight in clear ocean water at a depth of 30ft on the equater.
those numbers would change throughout the seasons, the Earth travels in an elliptical pattern around the sun and is closer at times then at others. in the northern hemisphere when the Earth is closer to the sun it's winter
  #35  
Old 09/30/2007, 10:06 AM
sabbath sabbath is offline
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Quote:
Originally posted by JetCat USA
those numbers would change throughout the seasons, the Earth travels in an elliptical pattern around the sun and is closer at times then at others. in the northern hemisphere when the Earth is closer to the sun it's winter
It would be beneficial to see how our lights compare though. I wonder what the range of this change in seasons would be. Or how we compare in winter or summer...
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  #36  
Old 09/30/2007, 10:14 AM
erbio erbio is offline
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LOL
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  #37  
Old 09/30/2007, 11:53 AM
xtm xtm is offline
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these PITAwatts are so PITA to calculate

Let's wait for Sanjay's review of the sun
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  #38  
Old 09/30/2007, 11:54 AM
Hypertek99 Hypertek99 is offline
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Ok so how many watts per gallon does the sun equal if anyone can find out the total amount of water in the ocean?
  #39  
Old 09/30/2007, 01:58 PM
NaH2Ofreak NaH2Ofreak is offline
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wait a minute......loading another bowl....
  #40  
Old 09/30/2007, 02:02 PM
Hypertek99 Hypertek99 is offline
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lol
  #41  
Old 09/30/2007, 02:27 PM
tkeracer619 tkeracer619 is offline
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Quote:
Originally posted by Hypertek99
Ok so how many watts per gallon does the sun equal if anyone can find out the total amount of water in the ocean?

1,056,115.85 Watts/Gallon

Earth has ~ 332,500,000 Cubic miles of water
1 Cubic Mile = 1,101,117,140,000 US Gallons
Sun has ~386,666,666,667,000,000,000,000,000 Watts per prior discussion.


386,666,666,667,000,000,000,000,000Watts/(332,500,000Miles^3 *(1,101,117,140,000G/Mile^3))=1,056,115.85 Watts/Gallon
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Last edited by tkeracer619; 09/30/2007 at 02:39 PM.
  #42  
Old 09/30/2007, 02:31 PM
sirjohn sirjohn is offline
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Quote:
Originally posted by virginiadiver69
Would T-5 be close enough or would I have to go with MH?
lol
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  #43  
Old 09/30/2007, 03:33 PM
cd77 cd77 is offline
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Can anyone recommend a company that produces a good fusion reactor light fixture? Kinda on a budget here.. just something simple.. I'll be happy to supply my own hydrogen and helium...
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  #44  
Old 09/30/2007, 03:43 PM
Hypertek99 Hypertek99 is offline
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So 400watts over a 29Gal is not overkill. LOL
  #45  
Old 09/30/2007, 05:21 PM
tkeracer619 tkeracer619 is offline
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Quote:
Originally posted by Hypertek99
So 400watts over a 29Gal is not overkill. LOL
If you custom make your reflectors I bet you could get (4) 1000W bulbs or more over that 29G
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  #46  
Old 09/30/2007, 05:56 PM
JetCat USA JetCat USA is offline
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I've ran a 400w 20kk XM over a 29 with excellent results, i just had to use a 6" wal-mart fan plus a 1/10hp chiller to keep temp in check.
  #47  
Old 09/30/2007, 08:47 PM
T Man T Man is offline
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Quote:
Originally posted by Pmolan
Did you just scan this in??

Indeed I did , someone had to back the facts up T
  #48  
Old 09/30/2007, 09:36 PM
jacmyoung jacmyoung is offline
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Quote:
Originally posted by tkeracer619
1,056,115.85 Watts/Gallon

Earth has ~ 332,500,000 Cubic miles of water
1 Cubic Mile = 1,101,117,140,000 US Gallons
Sun has ~386,666,666,667,000,000,000,000,000 Watts per prior discussion.


386,666,666,667,000,000,000,000,000Watts/(332,500,000Miles^3 *(1,101,117,140,000G/Mile^3))=1,056,115.85 Watts/Gallon
Not a fair number unless a motorized reflector is installed behind the Sun so it always faces the Earth as the Earth orbits the Sun.

How much aluminum is needed to make that reflector? Assume it will magically withstand the heat.
  #49  
Old 09/30/2007, 10:03 PM
cd77 cd77 is offline
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Just thought this was interesting -- according to Wikipedia, the earth receives 750 W / square meter from sunlight on a clear day: http://en.wikipedia.org/wiki/Orders_of_magnitude_(power)#Watt_2

Unfortunately, a reference isn't sited for this figure.
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  #50  
Old 09/30/2007, 10:21 PM
m2434 m2434 is offline
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Quote:
Originally posted by JetCat USA
those numbers would change throughout the seasons, the Earth travels in an elliptical pattern around the sun and is closer at times then at others. in the northern hemisphere when the Earth is closer to the sun it's winter
Barely, the orbit is ALMOST a perfect circle. There would be a slight change, but depending on your precision, would likely be lost to rounding error.

Here is some more info...

NASA

this is one of the weirdest threads I've seen... I like it!


 


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